The reaction of 1.250 g K with O2 forms 2.273 g of potassium superoxide, a substance used in self-contained breathing devices. Determine the formula for potassium superoxide.
Question
The reaction of 1.250 g K with O2 forms 2.273 g of potassium superoxide, a substance used in self-contained breathing devices. Determine the formula for potassium superoxide.
Solution
Sure, here are the steps to determine the formula for potassium superoxide:
-
First, we need to find the number of moles of potassium (K) and oxygen (O2) in the reaction.
-
The molar mass of potassium (K) is approximately 39.10 g/mol. So, the number of moles of K can be calculated as follows: Moles of K = mass of K / molar mass of K Moles of K = 1.250 g / 39.10 g/mol = 0.03198 mol
-
The mass of oxygen can be found by subtracting the mass of potassium from the total mass of potassium superoxide. Mass of O2 = mass of potassium superoxide - mass of K Mass of O2 = 2.273 g - 1.250 g = 1.023 g
-
The molar mass of oxygen (O2) is approximately 32.00 g/mol. So, the number of moles of O2 can be calculated as follows: Moles of O2 = mass of O2 / molar mass of O2 Moles of O2 = 1.023 g / 32.00 g/mol = 0.03196 mol
-
Now, we need to find the ratio of moles of K to O2 to determine the formula. The ratio can be found by dividing the number of moles of K by the number of moles of O2. Ratio = moles of K / moles of O2 Ratio = 0.03198 mol / 0.03196 mol = 1.0006
-
Since the ratio is approximately 1:1, the formula for potassium superoxide is KO2.
Similar Questions
Determine the chemical formula of potassium oxide.
Nitrogen monoxide and oxygen can be formed from the thermal decomposition of nitrogen dioxide.2NO2 (g) = 2NO (g) + O₂(g)In an experiment, 4 moles of nitrogen dioxide were put into a 1.0 dm³ container and heatedto a constant temperature. The equilibrium mixture contains 0.8 moles of oxygen.What is the value of the equilibrium constant, Kc?
Calculate the volume of oxygen gas produced at 69.97 atm and 24.36 oC by the complete decomposition of 96.2 g of potassium chlorate. The balanced equation for this reaction is …2KClO3 ⟶ 2KCl + 3O2
How many moles of KClO3 are needed to form 2.8 L of O2, measured at STP, according to the following reaction: 2KClO3 🡪 2KCl + 3O2
Potassium chlorate (used in fireworks, flares and safety matches) forms oxygen and potassium chloride when heated. KClO3(s) ⟶ KCl(s) + O2(g) [unbalanced]How many grams of oxygen are formed when 26.4 g of potassium chlorate is heated?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.