Which of the following options remain true for case constants in a switch construct?Select one:a.The code with the switch construct gives a compilation error when there is a duplicate case label   b.If no case matches but there is a default label, then all statements after the matching default label in the switch block are executed in sequence.      c.If no case matches and there is no default label, then no further action is taken and the switch statement completes abnormallyd.If any one of the case constants has a match with the expression, then all statements after the matching case label in the switch block are executed in sequencee.If no case matches and there is no default label, then it will result in a compilation error

The correct options are:

a. The code with the switch construct gives a compilation error when there is a duplicate case label. This is true because in a switch construct, each case must be unique. If there are duplicate case labels, the compiler will not know which one to execute when the condition matches the duplicate label.

d. If any one of the case constants has a match with the expression, then all statements after the matching case label in the switch block are executed in sequence. This is true because in a switch construct, once a match is found, all subsequent statements are executed until a break statement is encountered or the end of the switch block is reached.

The other options are not true:

b. If no case matches but there is a default label, then all statements after the matching default label in the switch block are executed in sequence. This is not true because only the statements within the default case are executed if no other case matches.

c. If no case matches and there is no default label, then no further action is taken and the switch statement completes abnormally. This is not true because the switch statement does not complete abnormally. It simply does nothing and execution continues with the next statement after the switch block.

e. If no case matches and there is no default label, then it will result in a compilation error. This is not true because it is not a requirement to have a default case in a switch construct. If no case matches and there is no default label, the switch statement simply does nothing.