To find the number of different combinations possible for the subcommittee, we can use the concept of combinations.

First, let's determine the number of ways to select two males from the four available. This can be calculated using the combination formula, which is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to be selected. In this case, we have 4 males and we want to select 2, so the calculation is 4C2 = 4! / (2!(4-2)!) = 6.

Next, we need to determine the number of ways to select two females from the three available. Using the same combination formula, we have 3C2 = 3! / (2!(3-2)!) = 3.

To find the total number of combinations, we multiply the number of ways to select males by the number of ways to select females. So, the total number of combinations is 6 * 3 = 18.

Therefore, the correct answer is A. 18.

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To find the number of different combinations possible for the subcommittee, we can use the concept of combinations.

First, let's determine the number of ways to select two males from the four available. This can be calculated using the combination formula, which is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to be selected. In this case, we have 4 males and we want to select 2, so the calculation is 4C2 = 4! / (2!(4-2)!) = 6.

Next, we need to determine the number of ways to select two females from the three available. Using the same combination formula, we have 3C2 = 3! / (2!(3-2)!) = 3.

To find the total number of combinations, we multiply the number of ways to select males by the number of ways to select females. So, the total number of combinations is 6 * 3 = 18.

Therefore, the correct answer is A. 18.

Knowee AI · Accepted Answer

To find the number of different combinations possible for the subcommittee, we can use the concept of combinations.

First, let's determine the number of ways to select two males from the four available. This can be calculated using the combination formula, which is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to be selected. In this case, we have 4 males and we want to select 2, so the calculation is 4C2 = 4! / (2!(4-2)!) = 6.

Next, we need to determine the number of ways to select two females from the three available. Using the same combination formula, we have 3C2 = 3! / (2!(3-2)!) = 3.

To find the total number of combinations, we multiply the number of ways to select males by the number of ways to select females. So, the total number of combinations is 6 * 3 = 18.

Therefore, the correct answer is A. 18.

A committee of national assembly comprises of four male and three female members. If a subcommittee consisting of two male and two female members is to be formed. How many different combinations are possible?A.18B.12C.7D.4

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