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Let F and G be functions from the set of all real numbers to itself. Define new functions F2G : R S R and G2F : R S R as follows: For every x [ R, (F2G)(x) 5 F(x)2G(x) (G2F )(x) 5 G(x)2F(x). Does F2G 5 G2F? Explain.

Question

Let F and G be functions from the set of all real numbers to itself. Define new functions F2G : R S R and G2F : R S R as follows: For every x [ R, (F2G)(x) 5 F(x)2G(x) (G2F )(x) 5 G(x)2F(x). Does F2G 5 G2F? Explain.

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Solution

The functions F2G and G2F are not necessarily equal.

The function F2G is defined as the product of the function F(x) and G(x), while G2F is defined as the product of G(x) and F(x).

In general, the multiplication of real numbers is commutative, meaning that the order in which the numbers are multiplied does not change the result. Therefore, if F(x) and G(x) are real numbers, then F(x) * G(x) = G(x) * F(x), so F2G(x) = G2F(x) for every x in the domain.

However, F(x) and G(x) are not just real numbers, they are functions. If these functions are not commutative under multiplication (which is the case for many types of functions), then F2G and G2F are not necessarily equal.

For example, if F(x) = x and G(x) = x^2, then F2G(x) = x * x^2 = x^3, but G2F(x) = x^2 * x = x^3. In this case, F2G and G2F are equal.

But if F(x) = x and G(x) = sin(x), then F2G(x) = x * sin(x), but G2F(x) = sin(x) * x. These two functions are not equal because the multiplication of a linear function and a sinusoidal function is not commutative.

So, whether F2G equals G2F depends on the specific functions F and G.

This problem has been solved

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