n given Figure Pq parallel rs and l IA transversal intersecting pq and rs at a and b respectively ta and to are bisectors of angle qab and angle sba respectively find the measure of angle atb​

I'm sorry, but you didn't provide a specific question or the figure mentioned in your text. However, I can tell you generally how to solve such a problem.

If PQ is parallel to RS and line L is a transversal intersecting PQ and RS at A and B respectively, and TA and TB are bisectors of ∠QAB and ∠SBA respectively, then you can use the properties of parallel lines and angle bisectors to find the measure of ∠ATB.

Here are the steps:

1. Since PQ || RS, by the corresponding angles property, ∠QAB = ∠SBA.
2. Since TA and TB are angle bisectors, ∠TAS = 1/2 ∠QAB and ∠TBS = 1/2 ∠SBA.
3. Therefore, ∠TAS = ∠TBS.
4. ∠ATB is an exterior angle for ∠TAS and ∠TBS, so by the exterior angle property, ∠ATB = ∠TAS + ∠TBS.
5. Since ∠TAS = ∠TBS, ∠ATB = 2 * ∠TAS = ∠QAB.

So, the measure of ∠ATB is equal to the measure of ∠QAB.

Please provide the specific measures or the figure for a more accurate answer.

I'm sorry, but you didn't provide a specific question or the figure mentioned in your text. Could you please provide more details or clarify your question?