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What is the inverse of a 2x2 matrix A = [[a, b], [c, d]]?a.1/(ad-bc) * [[a, b], [c, d]]b.1/(ad+bc) * [[a, -b], [-c, d]]c.1/(ad+bc) * [[d, b], [c, a]]d.1/(ad-bc) * [[d, -b], [-c, a]]

Question

What is the inverse of a 2x2 matrix A = [[a, b], [c, d]]?a.1/(ad-bc) * [[a, b], [c, d]]b.1/(ad+bc) * [[a, -b], [-c, d]]c.1/(ad+bc) * [[d, b], [c, a]]d.1/(ad-bc) * [[d, -b], [-c, a]]

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Solution

The inverse of a 2x2 matrix A = [[a, b], [c, d]] is given by 1/(ad-bc) * [[d, -b], [-c, a]]. So, the correct answer is option d.

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