The mass of a particular substance is known to grow exponentially at a rate of 1.5% per day. Its initial mass was 230 grams and, after t days, it weighed 325 grams.The equation modelling this growth is.Use the method of taking logs to solve this equation for t, giving your answer correct to the nearest day.
Question
The mass of a particular substance is known to grow exponentially at a rate of 1.5% per day. Its initial mass was 230 grams and, after t days, it weighed 325 grams.The equation modelling this growth is.Use the method of taking logs to solve this equation for t, giving your answer correct to the nearest day.
Solution
The exponential growth formula is given by:
M = P * e^(rt)
where: M is the final amount (325 grams in this case), P is the initial amount (230 grams in this case), r is the rate of growth (1.5% or 0.015 as a decimal), and t is the time (in days, which we're trying to find).
First, we can substitute the known values into the equation:
325 = 230 * e^(0.015t)
Next, we can solve for e^(0.015t) by dividing both sides of the equation by 230:
e^(0.015t) = 325 / 230 = 1.41304348
Now, we can take the natural logarithm (ln) of both sides to solve for 0.015t:
ln(e^(0.015t)) = ln(1.41304348)
0.015t = ln(1.41304348)
Finally, we can solve for t by dividing both sides of the equation by 0.015:
t = ln(1.41304348) / 0.015
Using a calculator, we find that t ≈ 23.8 days.
Rounding to the nearest day, we get t = 24 days.
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