What will the value of $x be at the end of this script?<?PHP$x=0;$x=$x+1;echo $x.” value”;$x++;?>
Question
What will the value of x=0;x+1;echo x++;?>
Solution
At the end of this script, the value of $x will be 2.
Here is the step-by-step explanation:
- Initially, x = 0.
- The next line increments the value of x = x is 1.
- The echo statement outputs the value of x . " value". This will display "1 value".
- Finally, the x by 1 again. Now, $x becomes 2.
Therefore, the final value of $x is 2.
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