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What will the value of $x be at the end of this script?<?PHP$x=0;$x=$x+1;echo $x.” value”;$x++;?>

Question

What will the value of xbeattheendofthisscript?<?PHPx be at the end of this script?<?PHPx=0;x=x=x+1;echo x.value;x.” value”;x++;?>

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Solution

At the end of this script, the value of $x will be 2.

Here is the step-by-step explanation:

  1. Initially, xisassignedthevalueof0:x is assigned the value of 0: x = 0.
  2. The next line increments the value of xby1:x by 1: x = x+1.Now,x + 1. Now, x is 1.
  3. The echo statement outputs the value of xfollowedbythestring"value":echox followed by the string " value": echo x . " value". This will display "1 value".
  4. Finally, the x++statementincrementsthevalueofx++ statement increments the value of x by 1 again. Now, $x becomes 2.

Therefore, the final value of $x is 2.

This problem has been solved

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