An optical fiber has core-index of 1.480 and a cladding index of 1.478. What should be the core size for single mode operation at 1310nm?a.6.50μmb.7.31μmc.5.26μmd.8.71μm
Question
An optical fiber has core-index of 1.480 and a cladding index of 1.478. What should be the core size for single mode operation at 1310nm?a.6.50μmb.7.31μmc.5.26μmd.8.71μm
Solution
The core size for single mode operation in an optical fiber can be calculated using the formula for the V-number (also known as the normalized frequency):
V = 2π(a/λ)√(n1^2 - n2^2)
Where:
- a is the core radius
- λ is the wavelength
- n1 is the core refractive index
- n2 is the cladding refractive index
For single mode operation, the V-number must be less than or equal to 2.405.
Let's plug in the given values and solve for a:
2.405 = 2π(a/1310*10^-9)√((1.480)^2 - (1.478)^2)
Solving this equation for a will give us the core size for single mode operation.
Please note that the answer will be in meters, so you will need to convert it to micrometers (1 meter = 10^6 micrometers) to match the answer choices.
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