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A bag contains x + 2 black balls, x + 5 red balls and x + 8 white balls. The probability of getting a black ball is 1/4. What is the probability of getting three balls of different colours, when three balls are drawn?Question 25Answera.45/119b.23/119c.39/119d.27/119

Question

A bag contains x + 2 black balls, x + 5 red balls and x + 8 white balls. The probability of getting a black ball is 1/4. What is the probability of getting three balls of different colours, when three balls are drawn?Question 25Answera.45/119b.23/119c.39/119d.27/119

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Solution

First, let's find the value of x.

Given that the probability of drawing a black ball is 1/4, we can set up the following equation:

(x + 2) / (3x + 15) = 1/4

Solving for x gives us x = 2.

So, the bag contains 4 black balls, 7 red balls, and 10 white balls, for a total of 21 balls.

Next, let's find the probability of drawing three balls of different colors.

The probability of drawing one ball of each color is the product of the probabilities of drawing each ball, in any order.

So, the probability is (4/21) * (7/20) * (10/19) * 6 (since there are 6 different orders in which we can draw the balls).

This simplifies to 140/7980 = 7/399.

So, none of the given options is correct. The correct answer is 7/399.

This problem has been solved

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