X, Y, Z are the three states of matter . State X has more intermolecular space thanstate Y but less than Z, Z has more K.E at a given temperature than Y and Y hasmore interparticle force of attraction than X. Identify X ,Y, Z. Compare X, Y, Z onthe basis of Compressibility and fluidity
Question
X, Y, Z are the three states of matter . State X has more intermolecular space thanstate Y but less than Z, Z has more K.E at a given temperature than Y and Y hasmore interparticle force of attraction than X. Identify X ,Y, Z. Compare X, Y, Z onthe basis of Compressibility and fluidity
Solution
Based on the given information, we can identify X, Y, and Z as follows:
- X is the liquid state of matter. It has more intermolecular space than the solid state (Y) but less than the gaseous state (Z).
- Y is the solid state of matter. It has more interparticle force of attraction than the liquid state (X) and less kinetic energy at a given temperature than the gaseous state (Z).
- Z is the gaseous state of matter. It has more kinetic energy at a given temperature than the solid state (Y) and more intermolecular space than the liquid state (X).
Now, let's compare X, Y, and Z on the basis of compressibility and fluidity:
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Compressibility: Gases (Z) are highly compressible due to the large intermolecular spaces between them. Liquids (X) are slightly compressible, while solids (Y) are almost incompressible due to the close packing of particles.
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Fluidity: Gases (Z) have the highest fluidity due to the large intermolecular spaces and high kinetic energy. Liquids (X) have moderate fluidity, while solids (Y) have the least fluidity due to the strong interparticle forces of attraction.
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