There are five rods K, L, M, N and O. The weight of O is twice L. The weight of L is equal to the weights of K and M together. The weight of M is twice the weight of K. The weight of N is three times the weight of M. If the weight of N is 90 kg, what will be the weight of O? Question 14Answera.105kgb.120Kgc.90kgd.60Kg
Question
There are five rods K, L, M, N and O. The weight of O is twice L. The weight of L is equal to the weights of K and M together. The weight of M is twice the weight of K. The weight of N is three times the weight of M. If the weight of N is 90 kg, what will be the weight of O? Question 14Answera.105kgb.120Kgc.90kgd.60Kg
Solution
First, let's find the weight of each rod based on the information given:
- The weight of N is given as 90 kg.
- Since the weight of M is one third of N, the weight of M is 90/3 = 30 kg.
- The weight of K is half of M, so the weight of K is 30/2 = 15 kg.
- The weight of L is equal to the weights of K and M together, so the weight of L is 15 + 30 = 45 kg.
- The weight of O is twice L, so the weight of O is 2 * 45 = 90 kg.
So, the weight of O is 90 kg. Therefore, the answer is c. 90kg.
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