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Find the HCF of 2³ x 3² x 5 x 7^2; 2² x 5² x 7³ and 2³ x 5³ x 7².Options :A] 940B] 980C] 930D] 925

Question

Find the HCF of 2³ x 3² x 5 x 7^2; 2² x 5² x 7³ and 2³ x 5³ x 7².Options :A] 940B] 980C] 930D] 925

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Solution

To find the Highest Common Factor (HCF) of the given numbers, we need to take the lowest power of each prime factor common to all the numbers.

The prime factors are 2, 3, 5, and 7.

For 2, the lowest power is 2². For 3, the lowest power is 3², but it's not present in all numbers, so we ignore it. For 5, the lowest power is 5. For 7, the lowest power is 7².

So, the HCF is 2² x 5 x 7² = 4 x 5 x 49 = 980.

So, the answer is B] 980.

This problem has been solved

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