The functions 𝑗 and 𝑘 are given by 𝑗(𝑥)=log10(𝑥+1)-5log10(2-𝑥)+log103 𝑘(𝑥)=sec𝑥-cos𝑥.(i) Rewrite 𝑗(𝑥) as a single logarithm base 10 without negative exponents in any part of the expression. Your result should be of the form log10(expression).(ii) Rewrite 𝑘(𝑥) as a product involving tan𝑥 and sin𝑥 and no other trigonometric functions.
Question
The functions 𝑗 and 𝑘 are given by 𝑗(𝑥)=log10(𝑥+1)-5log10(2-𝑥)+log103 𝑘(𝑥)=sec𝑥-cos𝑥.(i) Rewrite 𝑗(𝑥) as a single logarithm base 10 without negative exponents in any part of the expression. Your result should be of the form log10(expression).(ii) Rewrite 𝑘(𝑥) as a product involving tan𝑥 and sin𝑥 and no other trigonometric functions.
Solution
(i) To rewrite 𝑗(𝑥) as a single logarithm base 10 without negative exponents, we need to use the properties of logarithms.
The properties of logarithms are as follows:
- log_b(mn) = log_b(m) + log_b(n)
- log_b(m/n) = log_b(m) - log_b(n)
- log_b(m^n) = nlog_b(m)
Using these properties, we can rewrite 𝑗(𝑥) as follows:
𝑗(𝑥) = log10(𝑥+1) - 5log10(2-𝑥) + log10(3)
= log10(𝑥+1) - log10((2-𝑥)^5) + log10(3)
= log10[(𝑥+1) * 3 / (2-𝑥)^5]
= log10[(3𝑥+3) / (2-𝑥)^5]
(ii) To rewrite 𝑘(𝑥) as a product involving tan𝑥 and sin𝑥 and no other trigonometric functions, we need to use the trigonometric identities.
The trigonometric identities are as follows:
- sec𝑥 = 1/cos𝑥
- tan𝑥 = sin𝑥/cos𝑥
Using these identities, we can rewrite 𝑘(𝑥) as follows:
𝑘(𝑥) = sec𝑥 - cos𝑥
= 1/cos𝑥 - cos𝑥
= (1 - cos^2𝑥) / cos𝑥
= sin^2𝑥 / cos𝑥
= sin𝑥 * (sin𝑥 / cos𝑥)
= sin𝑥 * tan𝑥
Similar Questions
The functions 𝑔 and ℎ are given by 𝑔(𝑥)=log5(4𝑥-2) ℎ(𝑥)=sin-1(8𝑥).(i) Solve 𝑔(𝑥)=3 for values of 𝑥 in the domain of 𝑔.(ii) Solve ℎ(𝑥)=𝜋4 for values of 𝑥 in the domain of ℎ.
Use the rules of logarithms to write the following expression in terms of ln(𝑥) and ln(𝑦).ln(𝑥3𝑦)=
The properties of logarithms in this section can be used to rewrite log2𝑥5 as follows:𝐴log2𝐵Find the values for 𝐴 and 𝐵:
The function 𝑓 is given by 𝑓(𝑥)=𝑒2𝑥, and the function 𝑔 is given by 𝑔(𝑥)=ln(3𝑥). For 𝑥>0, which of the following is an expression for 𝑓(𝑔(𝑥)) ? Responses9𝑥29 x squared2𝑥+ln32 x plus ln 3(𝑒2𝑥)·ln(3𝑥)open parentheses e to the power of 2 x end exponent close parentheses times ln open parentheses 3 x close parentheses
The functions 𝑔 and ℎ are given by 𝑔(𝑥)=log4(2𝑥) ℎ(𝑥)=(𝑒𝑥)5𝑒(1/4).(i) Solve 𝑔(𝑥)=3 for values of 𝑥 in the domain of 𝑔.(ii) Solve ℎ(𝑥)=𝑒(1/2) for values of 𝑥 in the domain of ℎ.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.