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The functions 𝑗 and 𝑘 are given by          𝑗⁡(𝑥)=log10⁡(𝑥+1)-5⁢log10⁡(2-𝑥)+log10⁡3          𝑘⁡(𝑥)=sec⁡𝑥-cos⁡𝑥.(i) Rewrite 𝑗⁡(𝑥) as a single logarithm base 10 without negative exponents in any part of the expression. Your result should be of the form log10⁡(expression).(ii) Rewrite 𝑘⁡(𝑥) as a product involving tan⁡𝑥 and sin⁡𝑥 and no other trigonometric functions.

Question

The functions 𝑗 and 𝑘 are given by          𝑗⁡(𝑥)=log10⁡(𝑥+1)-5⁢log10⁡(2-𝑥)+log10⁡3          𝑘⁡(𝑥)=sec⁡𝑥-cos⁡𝑥.(i) Rewrite 𝑗⁡(𝑥) as a single logarithm base 10 without negative exponents in any part of the expression. Your result should be of the form log10⁡(expression).(ii) Rewrite 𝑘⁡(𝑥) as a product involving tan⁡𝑥 and sin⁡𝑥 and no other trigonometric functions.

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Solution

(i) To rewrite 𝑗(𝑥) as a single logarithm base 10 without negative exponents, we need to use the properties of logarithms.

The properties of logarithms are as follows:

  1. log_b(mn) = log_b(m) + log_b(n)
  2. log_b(m/n) = log_b(m) - log_b(n)
  3. log_b(m^n) = nlog_b(m)

Using these properties, we can rewrite 𝑗(𝑥) as follows:

𝑗(𝑥) = log10(𝑥+1) - 5log10(2-𝑥) + log10(3)

= log10(𝑥+1) - log10((2-𝑥)^5) + log10(3)

= log10[(𝑥+1) * 3 / (2-𝑥)^5]

= log10[(3𝑥+3) / (2-𝑥)^5]

(ii) To rewrite 𝑘(𝑥) as a product involving tan𝑥 and sin𝑥 and no other trigonometric functions, we need to use the trigonometric identities.

The trigonometric identities are as follows:

  1. sec𝑥 = 1/cos𝑥
  2. tan𝑥 = sin𝑥/cos𝑥

Using these identities, we can rewrite 𝑘(𝑥) as follows:

𝑘(𝑥) = sec𝑥 - cos𝑥

= 1/cos𝑥 - cos𝑥

= (1 - cos^2𝑥) / cos𝑥

= sin^2𝑥 / cos𝑥

= sin𝑥 * (sin𝑥 / cos𝑥)

= sin𝑥 * tan𝑥

This problem has been solved

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