What is the output of the following code?#include <stdio.h>int main() {    int arr[] = {1, 2, 3, 4, 5};    int *p = arr;    printf("%d\n", *(p + 3));    return 0;}

The output of the code will be 4.

Here's the step by step explanation:

1. An integer array arr[] is declared and initialized with the values {1, 2, 3, 4, 5}.

2. A pointer *p is declared and it is pointed to the base address of the array arr[]. So, p is pointing to the first element of the array, which is 1.

3. In the printf statement, *(p + 3) is used. Here, p + 3 means the address of the 4th element in the array (since array indexing starts from 0). So, *(p + 3) is the value at the address p + 3, which is the 4th element of the array arr[].

4. Therefore, 4 is printed as the output.