To solve this problem, we need to find the total distance covered, the total time taken, and then use the formula for average speed, which is total distance divided by total time.

Step 1: Let's assume the total distance covered is 2D (for simplicity of calculation). So, the first half distance is D and the second half distance is also D.

Step 2: The first half of the distance is covered with a speed of 3 m/s. So, the time taken to cover this distance is distance/speed = D/3.

Step 3: The second half of the distance is covered in two equal time intervals with speeds of 4.5 m/s and 7.5 m/s. Let's assume each time interval is T. So, the distances covered in these intervals are speed*time = 4.5T and 7.5T. Since these two distances add up to D, we have 4.5T + 7.5T = D. Solving this equation gives T = D/12.

Step 4: So, the total time taken for the journey is D/3 (for the first half) + 2*(D/12) (for the two equal intervals in the second half) = D/3 + D/6 = D/2.

Step 5: The average speed is total distance divided by total time = 2D / (D/2) = 4 m/s.

So, the average speed of the particle during this motion is 4 m/s.

Question

To solve this problem, we need to find the total distance covered, the total time taken, and then use the formula for average speed, which is total distance divided by total time.

Step 1: Let's assume the total distance covered is 2D (for simplicity of calculation). So, the first half distance is D and the second half distance is also D.

Step 2: The first half of the distance is covered with a speed of 3 m/s. So, the time taken to cover this distance is distance/speed = D/3.

Step 3: The second half of the distance is covered in two equal time intervals with speeds of 4.5 m/s and 7.5 m/s. Let's assume each time interval is T. So, the distances covered in these intervals are speed*time = 4.5T and 7.5T. Since these two distances add up to D, we have 4.5T + 7.5T = D. Solving this equation gives T = D/12.

Step 4: So, the total time taken for the journey is D/3 (for the first half) + 2*(D/12) (for the two equal intervals in the second half) = D/3 + D/6 = D/2.

Step 5: The average speed is total distance divided by total time = 2D / (D/2) = 4 m/s.

So, the average speed of the particle during this motion is 4 m/s.

Knowee AI · Accepted Answer

To solve this problem, we need to find the total distance covered, the total time taken, and then use the formula for average speed, which is total distance divided by total time.

Step 1: Let's assume the total distance covered is 2D (for simplicity of calculation). So, the first half distance is D and the second half distance is also D.

Step 2: The first half of the distance is covered with a speed of 3 m/s. So, the time taken to cover this distance is distance/speed = D/3.

Step 3: The second half of the distance is covered in two equal time intervals with speeds of 4.5 m/s and 7.5 m/s. Let's assume each time interval is T. So, the distances covered in these intervals are speed*time = 4.5T and 7.5T. Since these two distances add up to D, we have 4.5T + 7.5T = D. Solving this equation gives T = D/12.

Step 4: So, the total time taken for the journey is D/3 (for the first half) + 2*(D/12) (for the two equal intervals in the second half) = D/3 + D/6 = D/2.

Step 5: The average speed is total distance divided by total time = 2D / (D/2) = 4 m/s.

So, the average speed of the particle during this motion is 4 m/s.

A particle moving in a straight line covers half the distance with speed of 3 m/s. The another half of the distance is covered in two equal time intervals with speed of 4.5 m/s and 7.5 m/s, respectively. The average speed of the particle during this motion is

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