Sum of present ages of A, B and C is 72 years. If 4 years ago, their ages were in the ratio of 1 : 2 : 3, find A's present ageA7 YearsB10 YearsC12 YearsD14 Years

Let's solve this step by step:

Step 1: Let's assume the present ages of A, B, and C are a, b, and c respectively. According to the problem, a + b + c = 72.

Step 2: Four years ago, their ages were (a-4), (b-4), and (c-4). The problem states that these ages were in the ratio of 1:2:3. So, we can write these equations:

(a-4)/1 = (b-4)/2 = (c-4)/3

Step 3: From the above, we can say that (b-4) = 2(a-4) and (c-4) = 3(a-4).

Step 4: Substituting the values of b and c from step 3 into the equation from step 1, we get:

a + 2(a-4) + 4 + 3(a-4) + 4 = 72

Step 5: Simplifying the above equation, we get:

6a - 8 = 72

Step 6: Solving for a, we get:

a = (72 + 8) / 6 = 80 / 6 = 13.33

Since age cannot be in decimal, there seems to be a mistake in the problem or the options provided. None of the options A, B, C, or D are correct.