The vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at NTP will be (a) 22.4 L (b) 11.2 L (c) 1 L (d) 44.8 L

The vapour density of a gas is given by the formula:

Vapour Density = Molecular Weight / 2

Given that the vapour density of the gas is 11.2, we can find the molecular weight of the gas by rearranging the formula:

Molecular Weight = Vapour Density * 2 = 11.2 * 2 = 22.4 g/mol

At Normal Temperature and Pressure (NTP), one mole of any gas occupies a volume of 22.4 liters. Therefore, 22.4 g of the gas will occupy a volume of 22.4 liters.

However, we are asked to find the volume occupied by 11.2 g of the gas. Since the volume is directly proportional to the mass, we can find the volume occupied by 11.2 g of the gas by dividing the volume occupied by 22.4 g of the gas by 2:

Volume = 22.4 L / 2 = 11.2 L

Therefore, the volume occupied by 11.2 g of the gas at NTP is 11.2 liters. So, the correct answer is (b) 11.2 L.

The vapour density of a gas is given by the formula:

Vapour Density = Molecular Weight / 2

Given that the vapour density of the gas is 11.2, we can find the molecular weight of the gas by rearranging the formula:

Molecular Weight = Vapour Density * 2 = 11.2 * 2 = 22.4 g/mol

At Normal Temperature and Pressure (NTP), one mole of any gas occupies a volume of 22.4 liters. Therefore, 22.4 g of the gas will occupy a volume of 22.4 liters.

However, we are asked to find the volume occupied by 11.2 g of the gas. To find this, we can set up a proportion:

22.4 g : 22.4 L = 11.2 g : x L

Solving for x gives us:

x = (11.2 g * 22.4 L) / 22.4 g = 11.2 L

Therefore, 11.2 g of the gas at NTP will occupy a volume of 11.2 liters. So, the correct answer is (b) 11.2 L.