What will be the output of the following Python code?odd_numbers=lambda c: bool(c%2)number=[j for j in range(10)]print(number)n=list()for k in number: if odd_numbers(k): continue else: breakOptions [0, 1, 2, 3, 4, 5, 6, 7, 8, 9][0, 2, 4, 6, 8, 10][1, 3, 5, 7, 9]Error
Question
What will be the output of the following Python code?odd_numbers=lambda c: bool(c%2)number=[j for j in range(10)]print(number)n=list()for k in number: if odd_numbers(k): continue else: breakOptions [0, 1, 2, 3, 4, 5, 6, 7, 8, 9][0, 2, 4, 6, 8, 10][1, 3, 5, 7, 9]Error
Solution
The output of the given Python code will be an Error.
Here's why:
-
The code defines a lambda function
odd_numbersthat takes an argumentcand returnsTrueifcis odd andFalseifcis even. -
The code then creates a list
numberof integers from 0 to 9. -
The code then initializes an empty list
n. -
The code then enters a loop over each
kinnumber. Ifkis odd (i.e.,odd_numbers(k)returnsTrue), the code continues to the next iteration of the loop. Ifkis even (i.e.,odd_numbers(k)returnsFalse), the code breaks out of the loop. -
However, the code never uses the list
nor prints anything other than the listnumber. Therefore, the only output of the code is[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]. -
But the code is not properly formatted. The lines are not properly indented, which will cause a syntax error in Python. Therefore, the correct answer is "Error".
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