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What will be the output of the following Python code?odd_numbers=lambda c: bool(c%2)number=[j for j in range(10)]print(number)n=list()for k in number:  if odd_numbers(k):    continue  else:    breakOptions [0, 1, 2, 3, 4, 5, 6, 7, 8, 9][0, 2, 4, 6, 8, 10][1, 3, 5, 7, 9]Error

Question

What will be the output of the following Python code?odd_numbers=lambda c: bool(c%2)number=[j for j in range(10)]print(number)n=list()for k in number:  if odd_numbers(k):    continue  else:    breakOptions [0, 1, 2, 3, 4, 5, 6, 7, 8, 9][0, 2, 4, 6, 8, 10][1, 3, 5, 7, 9]Error

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Solution

The output of the given Python code will be an Error.

Here's why:

  1. The code defines a lambda function odd_numbers that takes an argument c and returns True if c is odd and False if c is even.

  2. The code then creates a list number of integers from 0 to 9.

  3. The code then initializes an empty list n.

  4. The code then enters a loop over each k in number. If k is odd (i.e., odd_numbers(k) returns True), the code continues to the next iteration of the loop. If k is even (i.e., odd_numbers(k) returns False), the code breaks out of the loop.

  5. However, the code never uses the list n or prints anything other than the list number. Therefore, the only output of the code is [0, 1, 2, 3, 4, 5, 6, 7, 8, 9].

  6. But the code is not properly formatted. The lines are not properly indented, which will cause a syntax error in Python. Therefore, the correct answer is "Error".

This problem has been solved

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