Calculate the difference in the formulae and molecular massesfor (a) CH3OH and C2H5OH (b) C2H5OH and C3H7OH, and (c) C3H7OHand C4H9OH.n Is there any similarity in these three?n Arrange these alcohols in the order of increasing carbon atoms toget a family. Can we call this family a homologous series?n Generate the homologous series for compounds containing up tofour carbons for the other functional groups given in Table 4.3.

The question seems to be a bit jumbled, but I'll try to answer it as best as I can.

(a) CH3OH and C2H5OH The molecular formula for CH3OH is CH4O and for C2H5OH is C2H6O. The molecular mass of CH3OH is 32.04 g/mol and for C2H5OH is 46.07 g/mol. The difference in molecular mass is 46.07 - 32.04 = 14.03 g/mol.

(b) C2H5OH and C3H7OH The molecular formula for C2H5OH is C2H6O and for C3H7OH is C3H8O. The molecular mass of C2H5OH is 46.07 g/mol and for C3H7OH is 60.1 g/mol. The difference in molecular mass is 60.1 - 46.07 = 14.03 g/mol.

(c) C3H7OH and C4H9OH The molecular formula for C3H7OH is C3H8O and for C4H9OH is C4H10O. The molecular mass of C3H7OH is 60.1 g/mol and for C4H9OH is 74.12 g/mol. The difference in molecular mass is 74.12 - 60.1 = 14.02 g/mol.

The similarity in these three is that the difference in molecular mass is approximately 14 g/mol, which corresponds to the molecular mass of a CH2 group. This indicates that each successive compound in the series has one more CH2 group than the previous one.

The alcohols can be arranged in order of increasing carbon atoms as follows: CH3OH, C2H5OH, C3H7OH, C4H9OH. This is indeed a homologous series, as each successive member differs by a CH2 group.

The homologous series for compounds containing up to four carbons for the other functional groups given in Table 4.3 would follow a similar pattern, with each successive member having one more CH2 group than the previous one. However, without the specific functional groups from Table 4.3, I can't provide the exact series.