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(f)     While a kettle boils, 0.018 kg of water changes to steam.Calculate the amount of energy required for this change.Specific latent heat of vaporisation of water = 2.3 × 10 6 J / kg.

Question

(f)     While a kettle boils, 0.018 kg of water changes to steam.Calculate the amount of energy required for this change.Specific latent heat of vaporisation of water = 2.3 × 10 6 J / kg.

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Solution

The energy required for a change of state can be calculated using the formula:

E = mL

where: E is the energy required, m is the mass of the substance, and L is the specific latent heat of the substance.

In this case, the mass (m) of the water is 0.018 kg and the specific latent heat of vaporisation (L) of water is 2.3 × 10^6 J/kg.

Substituting these values into the formula gives:

E = 0.018 kg * 2.3 × 10^6 J/kg

Therefore, the energy required for this change is approximately 41,400 Joules.

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