For the reaction 3 C2H2(g) → C6H6(l) at 25°C, the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K. Calculate the standard free energy change at 25°C.Group of answer choices-618 kJ-1061 kJ-503 kJ948 kJ
Question
For the reaction 3 C2H2(g) → C6H6(l) at 25°C, the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K. Calculate the standard free energy change at 25°C.Group of answer choices-618 kJ-1061 kJ-503 kJ948 kJ
Solution
The standard free energy change (ΔG°) can be calculated using the formula:
ΔG° = ΔH° - TΔS°
where: ΔH° is the standard enthalpy change, T is the temperature in Kelvin, and ΔS° is the standard entropy change.
Given: ΔH° = -631 kJ = -631,000 J (since 1 kJ = 1000 J) ΔS° = -430 J/K T = 25°C = 25 + 273.15 = 298.15 K (since absolute zero in Celsius is -273.15)
Substituting these values into the formula gives:
ΔG° = -631,000 J - (298.15 K * -430 J/K)
Solving this gives:
ΔG° = -631,000 J + 128,204.5 J = -502,795.5 J
Converting this back to kJ gives:
ΔG° = -502.8 kJ
So, the standard free energy change at 25°C is approximately -503 kJ.
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