What will be the output of the following C code #include <stdio.h> int main() { int x = 20; x %= 3; printf("%d",x); return 0; }
Question
What will be the output of the following C code #include <stdio.h> int main() { int x = 20; x %= 3; printf("%d",x); return 0; }
Solution
The output of the code will be 2.
Here's the step by step explanation:
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The code starts with including the standard input/output library of C.
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The main function is declared, which is the entry point of the program.
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An integer variable x is declared and initialized with the value 20.
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The next line
x %= 3;is a shorthand forx = x % 3;. The%operator is the modulus operator, which gives the remainder of the division of two numbers. So,x %= 3;means the value of x is updated to the remainder of the division of x by 3. As 20 divided by 3 gives a remainder of 2, the value of x becomes 2. -
The
printffunction is used to print the value of x, which is 2. -
The main function returns 0, indicating successful termination of the program.
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