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What will be the output of the following C code   #include <stdio.h> int main() { int x = 20;  x %= 3;  printf("%d",x); return 0; }

Question

What will be the output of the following C code   #include <stdio.h> int main() { int x = 20;  x %= 3;  printf("%d",x); return 0; }

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Solution

The output of the code will be 2.

Here's the step by step explanation:

  1. The code starts with including the standard input/output library of C.

  2. The main function is declared, which is the entry point of the program.

  3. An integer variable x is declared and initialized with the value 20.

  4. The next line x %= 3; is a shorthand for x = x % 3;. The % operator is the modulus operator, which gives the remainder of the division of two numbers. So, x %= 3; means the value of x is updated to the remainder of the division of x by 3. As 20 divided by 3 gives a remainder of 2, the value of x becomes 2.

  5. The printf function is used to print the value of x, which is 2.

  6. The main function returns 0, indicating successful termination of the program.

This problem has been solved

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