Consider the following C declaration. struct { short s[5]; union { float y; long z; }u; } t;Assume that objects of the type short, float and long occupy 2 bytes, 4 bytes and 8 bytes, respectively. The memory requirement for variable t, ignoring alignment considerations, isa.22 bytesb.14 bytesc.18 bytesd.10 bytes
Question
Consider the following C declaration. struct { short s[5]; union { float y; long z; }u; } t;Assume that objects of the type short, float and long occupy 2 bytes, 4 bytes and 8 bytes, respectively. The memory requirement for variable t, ignoring alignment considerations, isa.22 bytesb.14 bytesc.18 bytesd.10 bytes
Solution
To determine the memory requirement for variable t, we need to calculate the size of each member and add them together.
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The array of shorts, s[5], has 5 elements, and each element occupies 2 bytes. So the total memory occupied by s is 5 * 2 = 10 bytes.
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The union u has two members, a float y and a long z. Since they are part of a union, they share the same memory space. We need to consider the size of the largest member, which is the long z. The long type occupies 8 bytes.
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Adding the memory occupied by s and u, we get 10 + 8 = 18 bytes.
Therefore, the memory requirement for variable t is 18 bytes. Hence, the correct answer is option c.
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