What is the total number of oxygen atoms needed to form 120 g of sulfurous acid (H2SO3)? TYPE ONLY NUMERIC ANSWER IN SCIENTIFIC NOTATION AND CORRECT SIG FIGS.1 pointYour answer

First, we need to find the molar mass of sulfurous acid (H2SO3). The molar mass of H2SO3 is approximately 82.07 g/mol (1.01 g/mol for H * 2 + 32.06 g/mol for S + 16.00 g/mol for O * 3).

Next, we calculate the number of moles in 120 g of H2SO3. We do this by dividing the mass of the sample by the molar mass of H2SO3.

120 g / 82.07 g/mol = 1.46 mol

Each molecule of H2SO3 contains 3 oxygen atoms. Therefore, the number of moles of oxygen atoms in 1.46 mol of H2SO3 is 1.46 mol * 3 = 4.38 mol.

Finally, we convert moles of oxygen atoms to number of atoms using Avogadro's number (6.022 x 10^23 atoms/mol).

4.38 mol * 6.022 x 10^23 atoms/mol = 2.64 x 10^24 atoms

So, the total number of oxygen atoms needed to form 120 g of sulfurous acid is approximately 2.64 x 10^24.