Chemical A and Chemical B are mixed in the ratio of 5 : __. The final quantity of the combined chemicals is 190 ml . The amount of chemical A is 50 ml, the amount of chemical B is __ml. Find the missing number in the ratio for Chemical B.
Question
Chemical A and Chemical B are mixed in the ratio of 5 : __. The final quantity of the combined chemicals is 190 ml . The amount of chemical A is 50 ml, the amount of chemical B is __ml.
Find the missing number in the ratio for Chemical B.
Solution
To find the missing number in the ratio for Chemical B, we first need to understand that the ratio given (5:__) is the ratio of Chemical A to Chemical B.
Given that the amount of Chemical A is 50 ml, we can say that 5 parts (in the ratio) is equal to 50 ml.
To find out what 1 part is equal to, we divide 50 ml by 5.
50 ml / 5 = 10 ml.
So, 1 part is equal to 10 ml.
The total quantity of the combined chemicals is 190 ml. If we subtract the quantity of Chemical A from this, we get the quantity of Chemical B.
190 ml - 50 ml = 140 ml.
So, the quantity of Chemical B is 140 ml.
To find out how many parts this is (in the ratio), we divide 140 ml by 10 ml (since we found out earlier that 1 part is equal to 10 ml).
140 ml / 10 ml = 14.
So, the missing number in the ratio for Chemical B is 14.
Therefore, the ratio of Chemical A to Chemical B is 5:14.
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