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Mohamad and Vanessa have both recently started their own small businesses, and neither of them initially have any clients. Over the first year, Mohamad's client base increased by $$17 per month, while Vanessa's client base increased by $$5 in its first month, $$10 in its second month, $$15 in its third month, and so on.

Question

Mohamad and Vanessa have both recently started their own small businesses, and neither of them initially have any clients. Over the first year, Mohamad's client base increased by 17 per month, while Vanessa's client base increased by 5 in its first month, 10 in its second month, 15 in its third month, and so on.

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Solution

Sure, let's break down the problem step by step.

  1. Mohamad's Client Base Growth:

    • Mohamad's client base increases by 17 per month.
    • This means that after 1 month, he has 17 clients.
    • After 2 months, he has 17 \times 2 = 34 clients.
    • After 3 months, he has 17 \times 3 = 51 clients.
    • This pattern continues linearly.
  2. Vanessa's Client Base Growth:

    • Vanessa's client base increases in an arithmetic sequence.
    • In the first month, she gains 5 clients.
    • In the second month, she gains 10 clients.
    • In the third month, she gains 15 clients.
    • This means that in the nth month, she gains 5n clients.
  3. Calculating Total Clients for Vanessa:

    • To find the total number of clients Vanessa has after a certain number of months, we need to sum the arithmetic sequence.
    • The sum of the first n terms of an arithmetic sequence where the first term is a and the common difference is d is given by: Sn=n2×(2a+(n1)d) S_n = \frac{n}{2} \times (2a + (n-1)d)
    • For Vanessa, a=5a = 5 and d=5d = 5.
    • Therefore, the sum of clients after n months is: Sn=n2×(2×5+(n1)×5)=n2×(10+5n5)=n2×(5n+5)=n2×5(n+1)=5n(n+1)2 S_n = \frac{n}{2} \times (2 \times 5 + (n-1) \times 5) = \frac{n}{2} \times (10 + 5n - 5) = \frac{n}{2} \times (5n + 5) = \frac{n}{2} \times 5(n + 1) = \frac{5n(n + 1)}{2}
  4. Comparing Client Bases:

    • To find when Vanessa's client base equals or exceeds Mohamad's, we set their client base equations equal to each other: 17n=5n(n+1)2 17n = \frac{5n(n + 1)}{2}
    • Solving for n: 34n=5n(n+1) 34n = 5n(n + 1) 34n=5n2+5n 34n = 5n^2 + 5n 5n229n=0 5n^2 - 29n = 0 n(5n29)=0 n(5n - 29) = 0
    • This gives us n=0n = 0 or n=295=5.8n = \frac{29}{5} = 5.8.
  5. Conclusion:

    • Since n must be a whole number, we round up to the next whole number, which is 6.
    • Therefore, after 6 months, Vanessa's client base will exceed Mohamad's client base.

This problem has been solved

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