99% of a first order reaction, was completed in 32 minute. When will 99.9% of the reaction complete?
Question
99% of a first order reaction, was completed in 32 minute. When will 99.9% of the reaction complete?
Solution
To solve this problem, we need to use the formula for a first order reaction, which is:
t = (1/k) * ln([A]0/[A])
where:
- t is the time,
- k is the rate constant,
- [A]0 is the initial concentration,
- [A] is the concentration at time t.
From the problem, we know that 99% of the reaction is completed in 32 minutes. This means that [A] is 1% of [A]0. So we can write:
32 = (1/k) * ln([A]0/(0.01*[A]0))
Solving for k gives:
k = ln(100)/32
Now, we want to find out when 99.9% of the reaction will be complete. This means that [A] is 0.1% of [A]0. So we can write:
t = (1/k) * ln([A]0/(0.001*[A]0))
Substituting the value of k we found earlier gives:
t = 32 * ln(1000)/ln(100)
Calculating this gives:
t ≈ 48 minutes
So, 99.9% of the reaction will be complete in approximately 48 minutes.
Similar Questions
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