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A person buys 18 local tickets for Rs 110. Each first class ticket costs Rs 10and each second class ticket costs Rs 3. What will another lot of 18 tickets inwhich the numbers of first class and second class tickets are interchanged cost

Question

A person buys 18 local tickets for Rs 110. Each first class ticket costs Rs 10and each second class ticket costs Rs 3. What will another lot of 18 tickets inwhich the numbers of first class and second class tickets are interchanged cost

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Solution

Let's break down the problem:

  1. We know that the total cost of 18 tickets is Rs 110.

  2. Let's assume the number of first class tickets is 'x' and the number of second class tickets is 'y'.

  3. From the problem, we know that the cost of each first class ticket is Rs 10 and each second class ticket is Rs 3.

  4. Therefore, the total cost of the tickets can be represented as 10x + 3y = 110.

  5. We also know that the total number of tickets is 18, so x + y = 18.

  6. We now have a system of two equations, and we can solve for x and y.

  7. Subtract the second equation from the first to get 7x = 92, so x = 13.2. But the number of tickets must be an integer, so this is not possible.

  8. Therefore, there must be a mistake in the problem as it is not possible to buy a fraction of a ticket.

  9. If the numbers of first class and second class tickets are interchanged, the cost would also be impossible to calculate accurately due to the fractional ticket issue.

This problem has been solved

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