Calculate the molar mass of Ca(BO2)2·6H2O.

Sure, here's how you calculate the molar mass of Ca(BO2)2·6H2O:

1. First, you need to find the molar mass of each individual element in the compound. You can find these values on the periodic table. The molar mass of calcium (Ca) is approximately 40.08 g/mol, boron (B) is 10.81 g/mol, oxygen (O) is 16.00 g/mol, and hydrogen (H) is 1.01 g/mol.

2. Next, you need to multiply the molar mass of each element by the number of atoms of that element in the compound. For calcium, there is 1 atom, so its total molar mass is 40.08 g/mol. For boron, there are 2 atoms (from BO2) times 2 (from the subscript 2 after BO2), so its total molar mass is 10.81 g/mol * 2 * 2 = 43.24 g/mol. For oxygen, there are 2 atoms (from BO2) times 2 (from the subscript 2 after BO2) plus 6 (from 6H2O), so its total molar mass is 16.00 g/mol * 2 * 2 + 16.00 g/mol * 6 = 192.00 g/mol. For hydrogen, there are 2 atoms (from H2O) times 6 (from the subscript 6 before H2O), so its total molar mass is 1.01 g/mol * 2 * 6 = 12.12 g/mol.

3. Finally, you add up the total molar mass of each element to find the molar mass of the compound. So, the molar mass of Ca(BO2)2·6H2O is 40.08 g/mol + 43.24 g/mol + 192.00 g/mol + 12.12 g/mol = 287.44 g/mol.