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Step 4 (2 pts). Use a loop to process each element of the names and debt arrays to count the number of customers that have debt higher than the specified debt limit and the number of customers that have no debt. Output all results. Submit for grading to confirm six tests pass.Ex: If input is:2000 250 P TXthe output is:U.S. ReportCustomers: 2000Highest debt: SullivanCustomer names that start with 'P': 111Customers with debt over $250: 1562Customers debt free: 438

Question

Step 4 (2 pts). Use a loop to process each element of the names and debt arrays to count the number of customers that have debt higher than the specified debt limit and the number of customers that have no debt. Output all results. Submit for grading to confirm six tests pass.Ex: If input is:2000 250 P TXthe output is:U.S. ReportCustomers: 2000Highest debt: SullivanCustomer names that start with 'P': 111Customers with debt over $250: 1562Customers debt free: 438

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Solution

The question seems to be asking for a solution in a programming language, but it doesn't specify which one. However, I'll provide a solution in Python, which is a common language for this type of task.

Here's a step-by-step guide on how to solve this:

  1. First, you need to have two arrays: names and debt. These should be filled with the data of the customers. The names array should contain the names of the customers and the debt array should contain the corresponding debt of each customer.

  2. Initialize two counters to zero: debt_higher_than_limit and debt_free.

  3. Use a for loop to iterate over the debt array. For each element in the debt array, check if it's higher than the specified debt limit. If it is, increment the debt_higher_than_limit counter. If it's zero, increment the debt_free counter.

  4. After the loop, print the results.

Here's a Python code snippet that implements the above steps:

names = [...]  # fill with customer names
debt = [...]  # fill with corresponding customer debt
debt_limit = 250

debt_higher_than_limit = 0
debt_free = 0

for i in range(len(debt)):
    if debt[i] > debt_limit:
        debt_higher_than_limit += 1
    elif debt[i] == 0:
        debt_free += 1

print("Customers with debt over $", debt_limit, ": ", debt_higher_than_limit)
print("Customers debt free: ", debt_free)

Please replace the names and debt arrays with your actual data. Also, adjust the debt_limit variable to the value you want to check against.

This problem has been solved

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Step 3 (2 pts). Use a loop to process each element of the names array to count all customer names that begin with the specified letter. Ex: How many customer names begin with 'B' or 'L'? Output the number of customer names that start with the specified letter. Submit for grading to confirm four tests pass.Ex: If input is:1000 250 P TXthe output is:U.S. ReportCustomers: 1000Highest debt: SullivanCustomer names that start with 'P': 57

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1/1

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