Which equation represents the line that has a slope of $\frac{1}{3}$13 and an x-intercept of $5$5 ?
Question
Which equation represents the line that has a slope of 13 and an x-intercept of 5 ?
Solution
The equation of a line can be represented in slope-intercept form as y = mx + b, where m is the slope and b is the y-intercept.
However, in this case, we are given the slope (m = 1/3) and the x-intercept. The x-intercept is the point where the line crosses the x-axis, which is when y = 0.
So, we can set up the equation as follows:
0 = 1/3 * 5 + b
Solving for b, we get b = -5/3.
Therefore, the equation of the line is y = 1/3x - 5/3.
Similar Questions
Which equation represents the line that has a slope of $\frac{1}{3}$13 and an x-intercept of $5$5 ?ResponsesA. $y-5=$y−5= $\frac{1}{3}$13 $x$xA. y minus 5 is equal to 1 thirdx - no response givenC. $y-0=$y−0= $\frac{1}{3}$13 $\left(x+5\right)$(x+5)C. y minus 0 is equal to 1 thirdopen paren x plus 5 close paren - incorrectB. $y-0=$y−0= $\frac{1}{3}$13 $\left(x-5\right)$(x−5)B. y minus 0 is equal to 1 thirdopen paren x minus 5 close paren - no response givenD. $y-5=$y−5= $\frac{1}{3}$13 $\left(x-5\right)$
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line has a slope of 0 and passes through the point (3, -5). Which of the following equations represents the line?
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