A 800 g object displaces 500 mL of water. What is its specific gravity?
Question
A 800 g object displaces 500 mL of water. What is its specific gravity?
Solution
Sure, here are the steps to calculate the specific gravity:
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First, we need to convert the mass of the object from grams to kilograms because the standard unit of mass in physics is kilogram. So, 800 g = 0.8 kg.
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The volume of water displaced by the object is given as 500 mL. We need to convert this to cubic meters (m^3), the standard unit of volume in physics. 1 mL = 1e-6 m^3, so 500 mL = 500 * 1e-6 = 0.0005 m^3.
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The density of the object can be calculated using the formula: Density = Mass/Volume. So, the density of the object = 0.8 kg / 0.0005 m^3 = 1600 kg/m^3.
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The specific gravity of an object is the ratio of the density of the object to the density of a reference substance. The reference substance is usually water at 4 degrees Celsius, which has a density of 1000 kg/m^3.
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Therefore, the specific gravity of the object = Density of object / Density of water = 1600 kg/m^3 / 1000 kg/m^3 = 1.6.
So, the specific gravity of the object is 1.6.
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