5 men and 4 women are to be seated in a row so that the women occupy the even places. How many such arrangements are possible?Choices:- 2245 1284 2880 2546
Question
5 men and 4 women are to be seated in a row so that the women occupy the even places. How many such arrangements are possible?Choices:- 2245 1284 2880 2546
Solution
To solve this problem, we need to understand that we are dealing with permutations, which is a way of arranging items where the order is important.
Step 1: Determine the number of even places. Since there are 9 people in total, there are 4 even places (2nd, 4th, 6th, 8th).
Step 2: Determine the number of ways to arrange the women. Since there are 4 women and 4 even places, the number of ways to arrange the women is 4!, which equals 24.
Step 3: Determine the number of ways to arrange the men. Since there are 5 men and 5 remaining places (1st, 3rd, 5th, 7th, 9th), the number of ways to arrange the men is 5!, which equals 120.
Step 4: Multiply the number of ways to arrange the women and the men to get the total number of arrangements. So, 24 * 120 = 2880.
Therefore, the number of such arrangements possible is 2880. So, the correct answer is 2880.
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