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Consider the following integral. Sketch its region of integration in the xy-plane.∫20∫e2eyxln(x)dxdy∫02∫𝑒𝑦𝑒2𝑥ln(𝑥)𝑑𝑥𝑑𝑦(a) Which graph shows the region of integration in the xy-plane? (b) Write the integral with the order of integration reversed:∫20∫e2eyxln(x)dxdy=∫BA∫DCxln(x)dydx∫02∫𝑒𝑦𝑒2𝑥ln(𝑥)𝑑𝑥𝑑𝑦=∫𝐴𝐵∫𝐶𝐷𝑥ln(𝑥)𝑑𝑦𝑑𝑥with limits of integration

Question

Consider the following integral. Sketch its region of integration in the xy-plane.∫20∫e2eyxln(x)dxdy∫02∫𝑒𝑦𝑒2𝑥ln(𝑥)𝑑𝑥𝑑𝑦(a) Which graph shows the region of integration in the xy-plane? (b) Write the integral with the order of integration reversed:∫20∫e2eyxln(x)dxdy=∫BA∫DCxln(x)dydx∫02∫𝑒𝑦𝑒2𝑥ln(𝑥)𝑑𝑥𝑑𝑦=∫𝐴𝐵∫𝐶𝐷𝑥ln(𝑥)𝑑𝑦𝑑𝑥with limits of integration

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Solution

The given integral is a double integral, and it's written in the form ∫ from 0 to 2 ∫ from e^y to e^(2x) (xln(x)) dx dy.

(a) The region of integration in the xy-plane is defined by the limits of the integral. The outer integral is with respect to y and ranges from 0 to 2. The inner integral is with respect to x and ranges from e^y to e^(2x). This region is a vertical strip in the xy-plane that starts at the curve x=e^y and ends at the curve x=e^(2x), for y between 0 and 2.

(b) To reverse the order of integration, we need to describe the same region in terms of horizontal strips instead of vertical ones. We observe that x ranges from e^0=1 to e^(22)=e^4, and for a fixed x, y ranges from ln(x) to 1/2ln(x). Therefore, the integral with reversed order of integration is ∫ from 1 to e^4 ∫ from ln(x) to 1/2*ln(x) (xln(x)) dy dx.

This problem has been solved

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