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If in a number 5736456742, “1” is added to allthe even digits and “2” is subtracted from allthe odd digits. Then, which of the followingdigit/digits are repeated twice in the newnumber?

Question

If in a number 5736456742, “1” is added to allthe even digits and “2” is subtracted from allthe odd digits. Then, which of the followingdigit/digits are repeated twice in the newnumber?

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Solution

To find the digit/digits that are repeated twice in the new number, we need to follow the given instructions and perform the necessary operations on each digit of the original number.

  1. Start with the original number: 5736456742.

  2. Add 1 to all the even digits:

    • The even digits in the original number are 5, 6, 4, 6, and 4.
    • Adding 1 to each of these even digits, we get 6, 7, 5, 7, and 5.
  3. Subtract 2 from all the odd digits:

    • The odd digits in the original number are 7, 3, 5, 7, and 7.
    • Subtracting 2 from each of these odd digits, we get 5, 1, 3, 5, and 5.
  4. Combine the modified even and odd digits to form the new number:

    • The modified even digits are 6, 7, 5, 7, and 5.
    • The modified odd digits are 5, 1, 3, 5, and 5.
    • Combining these digits, we get the new number: 675753555.
  5. Identify the digit/digits that are repeated twice in the new number:

    • In the new number, the digit 5 is repeated twice.

Therefore, the digit 5 is the only digit that is repeated twice in the new number.

This problem has been solved

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