Calculate the temperature (in K) at which the resistance of a metal becomes20% more than its resistance at 300 K. The value of the temperature coefficientof resistance for this metal is 2.0 × 10-4 /K
Question
Calculate the temperature (in K) at which the resistance of a metal becomes20% more than its resistance at 300 K. The value of the temperature coefficientof resistance for this metal is 2.0 × 10-4 /K
Solution
To calculate the temperature at which the resistance of a metal becomes 20% more than its resistance at 300 K, we can use the temperature coefficient of resistance.
Step 1: Determine the resistance at 300 K. Let's assume the resistance at 300 K is R_300.
Step 2: Calculate the 20% increase in resistance. To find the 20% increase, we multiply the resistance at 300 K by 0.20: 20% increase = 0.20 * R_300
Step 3: Calculate the change in resistance. The change in resistance is the 20% increase in resistance minus the resistance at 300 K: Change in resistance = (0.20 * R_300) - R_300
Step 4: Calculate the temperature change. The temperature change can be found using the temperature coefficient of resistance. The formula is: Temperature change = (Change in resistance) / (Temperature coefficient of resistance)
Step 5: Calculate the temperature at which the resistance becomes 20% more. The temperature at which the resistance becomes 20% more than its resistance at 300 K is: Temperature = 300 K + Temperature change
By following these steps, you can calculate the temperature at which the resistance of the metal becomes 20% more than its resistance at 300 K.
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