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A series ac circuit consists of a voltage source of frequency 60 Hz and source voltage amplitude 345 volts, a 701-Q resistor, a 1.6 - uF capacitor, and an inductor of inductance L.(a) What must be the value of L for the phase angle to be zero? (b) When L has the value calculated in part (a), what is the current amplitude in the circuit?

Question

A series ac circuit consists of a voltage source of frequency 60 Hz and source voltage amplitude 345 volts, a 701-Q resistor, a 1.6 - uF capacitor, and an inductor of inductance L.(a) What must be the value of L for the phase angle to be zero? (b) When L has the value calculated in part (a), what is the current amplitude in the circuit?

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Solution

(a) For the phase angle to be zero in a series AC circuit, the inductive reactance (XL) must be equal to the capacitive reactance (XC).

The formula for capacitive reactance is XC = 1/(2πfC), where f is the frequency and C is the capacitance.

Substituting the given values, we get XC = 1/(2π60Hz1.6μF) = 1,663.5 Ohms.

Since XL must be equal to XC for the phase angle to be zero, XL = 1,663.5 Ohms.

The formula for inductive reactance is XL = 2πfL, where L is the inductance.

Rearranging this formula to solve for L, we get L = XL/(2πf).

Substituting the known values, we get L = 1,663.5 Ohms / (2π*60Hz) = 0.44 H.

So, the value of L for the phase angle to be zero is 0.44 H.

(b) When L has the value calculated in part (a), the total impedance (Z) of the circuit is equal to the resistance (R), since the inductive and capacitive reactances cancel each other out.

So, Z = R = 701 Ohms.

The formula for the current amplitude (I) in an AC circuit is I = V/Z, where V is the voltage amplitude.

Substituting the known values, we get I = 345 volts / 701 Ohms = 0.49 A.

So, the current amplitude in the circuit is 0.49 A.

This problem has been solved

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