Let's denote the usual speed of Prakash as S (in km/h for example), and the usual time he takes to cover the distance as T (in hours for example).

1. When Prakash walks with 6/7th of his usual speed, his speed becomes 6/7 * S.

2. The time it takes him to cover the same distance at this slower speed is the distance divided by the new speed. The distance is the usual speed times the usual time (S*T), and the new speed is 6/7 * S. So the new time is (S*T) / (6/7 * S) = 7/6 * T.

3. We know that this new time is the usual time plus 12 minutes, or T + 12/60 hours (since we're working in hours). So we can set up the equation 7/6 * T = T + 12/60.

4. Solving this equation for T gives T = 1 hour. So the usual time taken by Prakash to cover the distance is 1 hour.

Question

Let's denote the usual speed of Prakash as S (in km/h for example), and the usual time he takes to cover the distance as T (in hours for example).

1. When Prakash walks with 6/7th of his usual speed, his speed becomes 6/7 * S.

2. The time it takes him to cover the same distance at this slower speed is the distance divided by the new speed. The distance is the usual speed times the usual time (S*T), and the new speed is 6/7 * S. So the new time is (S*T) / (6/7 * S) = 7/6 * T.

3. We know that this new time is the usual time plus 12 minutes, or T + 12/60 hours (since we're working in hours). So we can set up the equation 7/6 * T = T + 12/60.

4. Solving this equation for T gives T = 1 hour. So the usual time taken by Prakash to cover the distance is 1 hour.

Knowee AI · Accepted Answer

Let's denote the usual speed of Prakash as S (in km/h for example), and the usual time he takes to cover the distance as T (in hours for example).

1. When Prakash walks with 6/7th of his usual speed, his speed becomes 6/7 * S.

2. The time it takes him to cover the same distance at this slower speed is the distance divided by the new speed. The distance is the usual speed times the usual time (S*T), and the new speed is 6/7 * S. So the new time is (S*T) / (6/7 * S) = 7/6 * T.

3. We know that this new time is the usual time plus 12 minutes, or T + 12/60 hours (since we're working in hours). So we can set up the equation 7/6 * T = T + 12/60.

4. Solving this equation for T gives T = 1 hour. So the usual time taken by Prakash to cover the distance is 1 hour.

Walking with 6/7th of his usual speed , Prakash was late by 12 minutes . What is the usual time taken by Prakash to cover the distance ?

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