2 = 6 kHz closed than what will be the value of fundamental frequency. 1 km. 020. A block of mass 4kg is allowed to move on an inclined plane of coefficient of raction(u= 0.4) i) Find the acceleration of block 2x21 ii) Find the time taken by block to move on the inclined plane from rest, if the length of in anc is 100m 21. A block of
Question
2 = 6 kHz closed than what will be the value of fundamental frequency. 1 km. 020. A block of mass 4kg is allowed to move on an inclined plane of coefficient of raction(u= 0.4) i) Find the acceleration of block 2x21 ii) Find the time taken by block to move on the inclined plane from rest, if the length of in anc is 100m 21. A block of
Solution
The question seems to be incomplete and a bit confusing. However, I'll try to answer the parts that I can understand.
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The fundamental frequency of a closed pipe is given by the formula f = v/4L, where v is the speed of sound and L is the length of the pipe. However, you've mentioned "2 = 6 kHz closed" which doesn't fit into this formula. Could you please clarify this part?
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For a block moving on an inclined plane, the acceleration can be found using the formula a = g(sinθ - μcosθ), where g is the acceleration due to gravity, θ is the angle of the incline, and μ is the coefficient of friction. However, the angle of the incline is not given in your question.
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The time taken by the block to move on the inclined plane from rest can be found using the formula t = sqrt(2d/a), where d is the distance (100m in this case) and a is the acceleration. However, as mentioned above, we need more information to calculate the acceleration.
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The last part of your question seems to be cut off. Could you please provide the full question?
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