To solve this problem, we can use a simple approach of iterating through the array and keeping track of the minimum price and the maximum profit we can get. Here are the steps:

1. Initialize two variables, `minPrice` and `maxProfit`. Set `minPrice` to the maximum possible value of an integer and `maxProfit` to 0.

2. Iterate through the array. For each price:

a. If the price is less than `minPrice`, update `minPrice` with the current price.

b. Calculate the potential profit by subtracting `minPrice` from the current price. If the potential profit is greater than `maxProfit`, update `maxProfit` with the potential profit.

3. After iterating through all prices, `maxProfit` will hold the maximum profit we can get.

Here is a Python code snippet that implements the above steps:

```python
def maxProfit(prices):
minPrice = float('inf')
maxProfit = 0
for price in prices:
minPrice = min(minPrice, price)
profit = price - minPrice
maxProfit = max(maxProfit, profit)
return maxProfit
```

In the first sample input, the function will return 5, which is the maximum profit we can get by buying the stock on day 2 and selling it on day 6. In the second sample input, the function will return 0, because the prices are decreasing every day, so there is no opportunity to make a profit.

Question

To solve this problem, we can use a simple approach of iterating through the array and keeping track of the minimum price and the maximum profit we can get. Here are the steps:

1. Initialize two variables, `minPrice` and `maxProfit`. Set `minPrice` to the maximum possible value of an integer and `maxProfit` to 0.

2. Iterate through the array. For each price:

a. If the price is less than `minPrice`, update `minPrice` with the current price.

b. Calculate the potential profit by subtracting `minPrice` from the current price. If the potential profit is greater than `maxProfit`, update `maxProfit` with the potential profit.

3. After iterating through all prices, `maxProfit` will hold the maximum profit we can get.

Here is a Python code snippet that implements the above steps:

```python
def maxProfit(prices):
    minPrice = float('inf')
    maxProfit = 0
    for price in prices:
        minPrice = min(minPrice, price)
        profit = price - minPrice
        maxProfit = max(maxProfit, profit)
    return maxProfit
```

In the first sample input, the function will return 5, which is the maximum profit we can get by buying the stock on day 2 and selling it on day 6. In the second sample input, the function will return 0, because the prices are decreasing every day, so there is no opportunity to make a profit.

Knowee AI · Accepted Answer

To solve this problem, we can use a simple approach of iterating through the array and keeping track of the minimum price and the maximum profit we can get. Here are the steps:

1. Initialize two variables, `minPrice` and `maxProfit`. Set `minPrice` to the maximum possible value of an integer and `maxProfit` to 0.

2. Iterate through the array. For each price:

a. If the price is less than `minPrice`, update `minPrice` with the current price.

b. Calculate the potential profit by subtracting `minPrice` from the current price. If the potential profit is greater than `maxProfit`, update `maxProfit` with the potential profit.

3. After iterating through all prices, `maxProfit` will hold the maximum profit we can get.

Here is a Python code snippet that implements the above steps:

```python
def maxProfit(prices):
    minPrice = float('inf')
    maxProfit = 0
    for price in prices:
        minPrice = min(minPrice, price)
        profit = price - minPrice
        maxProfit = max(maxProfit, profit)
    return maxProfit
```

In the first sample input, the function will return 5, which is the maximum profit we can get by buying the stock on day 2 and selling it on day 6. In the second sample input, the function will return 0, because the prices are decreasing every day, so there is no opportunity to make a profit.

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