What will be the output?public class Test{ public static void main(String[] args){ int[] a = new int[4]; a[1] = 1; a = new int[2]; System.out.println("a[1] is " + a[1]); }}The program has a compile error because new int[2]The program has a runtime error because a[1]a[1] is 0a[1] is 1Clear ResponseSave & Next
Question
What will be the output?public class Test{ public static void main(String[] args){ int[] a = new int[4]; a[1] = 1; a = new int[2]; System.out.println("a[1] is " + a[1]); }}The program has a compile error because new int[2]The program has a runtime error because a[1]a[1] is 0a[1] is 1Clear ResponseSave & Next
Solution
The output will be "a[1] is 0".
Here's the step by step explanation:
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An integer array 'a' of size 4 is created. By default, all elements in an integer array are initialized to 0 in Java. So, the array 'a' looks like this: [0, 0, 0, 0].
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The second element of the array (index 1) is set to 1. Now, the array 'a' looks like this: [0, 1, 0, 0].
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A new integer array 'a' of size 2 is created. This new array 'a' is completely separate from the previous array 'a'. All elements in this new array are also initialized to 0. So, the new array 'a' looks like this: [0, 0].
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The program prints the second element of the new array 'a' (index 1), which is 0. Hence, the output is "a[1] is 0".
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