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What will be the output when the following code is executed?public class Product {public static void main(String[] args) {                             LocalDate startLocalDate = LocalDate.of(2016, Month.JUNE, 01);LocalDate tempLocalDate = startLocalDate;startLocalDate.plusDays(10);System.out.println(tempLocalDate);}} 2016-06-0101-06-20162016-06-1111-06-2016

Question

What will be the output when the following code is executed?public class Product {public static void main(String[] args) {                             LocalDate startLocalDate = LocalDate.of(2016, Month.JUNE, 01);LocalDate tempLocalDate = startLocalDate;startLocalDate.plusDays(10);System.out.println(tempLocalDate);}} 2016-06-0101-06-20162016-06-1111-06-2016

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Solution

The output of the code will be "2016-06-01".

Here's the step by step explanation:

  1. A LocalDate object startLocalDate is created with the date 2016-06-01.
  2. A new LocalDate object tempLocalDate is created and assigned the same reference as startLocalDate.
  3. The plusDays(10) method is called on startLocalDate, but the result is not assigned to any variable. The plusDays method does not change the original LocalDate object, but instead returns a new LocalDate object with the added days. Since the result is not stored, this line effectively does nothing.
  4. The System.out.println(tempLocalDate); line prints the tempLocalDate, which still has the original date of 2016-06-01.

So, the output will be "2016-06-01".

This problem has been solved

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