You need 250.0 mL of a 0.0774 M solution of sodium nitrate to use in the laboratory. What volume of a 0.278 M stock solution would you need to dilute to achieve this concentration?Question 8Answer25.0 mL69.6 mL5.4 mL11618.6 mL10.0 mL

Two solutions were mixed together. One solution was 300 mL of 0.45 M sodium chloride. The other solution was 200 mL of 1.5 M sodium nitride. What was the final concentration of sodium ions in the solution? Question 4 options: 1.95 M 0.435 M 2.07 M 0.975 M 0.87 M

You wish to prepare 140.0 mL of a 3.0 M solution of NaOH by diluting a concentrated 10.0 M NaOH solution. What volume of the concentrated solution is required to do this?Group of answer choicesGroup of answer choices42 mL7.0 mL0.47 mL20 mL

If 211 mL of water is added to 5.00 mL of 3.24 M NaCl solution, what is the concentration of the new solution? ___ M Your answer should be rounded to two significant figures. Do not include units in your answer.

You have prepared a 2 M stock solution of an analyte you will be diluting to prepare your standard solutions.  What volume (in mL) will you need to add and dilute in a 250 mL volumetric flask to achieve a final concentration of 0.06 M?  Answer to 1 decimal place (Hint: C1V1=C2V2)

What volume of 0.0334 M KIO3 solution A is needed to make 25 mL of 0.005 M solution A?