In an A.P. T₁=11 and To = 16 then the sum of the first 40 term is 10 A 550 B 660 C 880 D

The given question is about an Arithmetic Progression (A.P.) where the first term (T₁) is 11 and the common difference (d) is 16 - 11 = 5.

The sum (S) of the first n terms of an A.P. can be calculated using the formula:

S = n/2 [2a + (n-1)d]

where: n = number of terms a = first term d = common difference

Substituting the given values into the formula:

S = 40/2 [2*11 + (40-1)*5] S = 20 [22 + 195] S = 20 * 217 S = 4340

However, the question states that the sum of the first 40 terms is 10, which contradicts the calculation. There seems to be a mistake in the question. The options provided (A 550, B 660, C 880, D) also do not match the calculated sum. Please check the question for any errors.