To solve this problem, we can use the method of simultaneous equations. Let's denote the cost of a book as 'b' and the cost of a notebook as 'n'.

From the problem, we have the following two equations:

1) 3b + 5n = 309
2) 6b + 2n = 282

We can simplify the second equation by dividing it by 2, which gives us:

3b + n = 141

Now we have two new equations:

1) 3b + 5n = 309
2) 3b + n = 141

Subtract the second equation from the first to eliminate 'b':

4n = 168

Divide by 4 to solve for 'n':

n = 42

Substitute n = 42 into the second equation:

3b + 42 = 141
3b = 99
b = 33

So, the cost of a book is Rs. 33 and the cost of a notebook is Rs. 42.

Question

To solve this problem, we can use the method of simultaneous equations. Let's denote the cost of a book as 'b' and the cost of a notebook as 'n'.

From the problem, we have the following two equations:

1) 3b + 5n = 309
2) 6b + 2n = 282

We can simplify the second equation by dividing it by 2, which gives us:

3b + n = 141

Now we have two new equations:

1) 3b + 5n = 309
2) 3b + n = 141

Subtract the second equation from the first to eliminate 'b':

4n = 168

Divide by 4 to solve for 'n':

n = 42

Substitute n = 42 into the second equation:

3b + 42 = 141
3b = 99
b = 33

So, the cost of a book is Rs. 33 and the cost of a notebook is Rs. 42.

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