To find the equation of the line normal to f(x) at the point x=1, we first need to know the function f(x). The normal line is perpendicular to the tangent line at that point, and the slope of the tangent line is given by the derivative of the function at that point.

Here are the steps:

1. Find the derivative of the function f(x), let's call it f'(x).
2. Evaluate f'(x) at x=1 to find the slope of the tangent line at that point.
3. The slope of the line normal (perpendicular) to the function at that point is the negative reciprocal of the slope of the tangent line. If the slope of the tangent line is m, then the slope of the normal line is -1/m.
4. The normal line will pass through the point (1, f(1)). So, you can use the point-slope form of the line equation to find the equation of the normal line: y - f(1) = -1/m * (x - 1).

Without knowing the specific function f(x), I can't provide a more specific answer.

Question

To find the equation of the line normal to f(x) at the point x=1, we first need to know the function f(x). The normal line is perpendicular to the tangent line at that point, and the slope of the tangent line is given by the derivative of the function at that point.

Here are the steps:

1. Find the derivative of the function f(x), let's call it f'(x).
2. Evaluate f'(x) at x=1 to find the slope of the tangent line at that point.
3. The slope of the line normal (perpendicular) to the function at that point is the negative reciprocal of the slope of the tangent line. If the slope of the tangent line is m, then the slope of the normal line is -1/m.
4. The normal line will pass through the point (1, f(1)). So, you can use the point-slope form of the line equation to find the equation of the normal line: y - f(1) = -1/m * (x - 1).

Without knowing the specific function f(x), I can't provide a more specific answer.

Knowee AI · Accepted Answer

To find the equation of the line normal to f(x) at the point x=1, we first need to know the function f(x). The normal line is perpendicular to the tangent line at that point, and the slope of the tangent line is given by the derivative of the function at that point.

Here are the steps:

1. Find the derivative of the function f(x), let's call it f'(x).
2. Evaluate f'(x) at x=1 to find the slope of the tangent line at that point.
3. The slope of the line normal (perpendicular) to the function at that point is the negative reciprocal of the slope of the tangent line. If the slope of the tangent line is m, then the slope of the normal line is -1/m.
4. The normal line will pass through the point (1, f(1)). So, you can use the point-slope form of the line equation to find the equation of the normal line: y - f(1) = -1/m * (x - 1).

Without knowing the specific function f(x), I can't provide a more specific answer.

What is the equation of the line normal to f(x) at the point x=1?

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