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If (a + b)/ c = 6/5 and (b + c ) / a = 9/2 then what is the value of (a + c )/b?Options9/57/117/411/7

Question

If (a + b)/ c = 6/5 and (b + c ) / a = 9/2 then what is the value of (a + c )/b?Options9/57/117/411/7

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Solution

The problem is a system of two equations with three variables. To solve for the value of (a + c) / b, we need to manipulate the given equations to find a relationship between a, b, and c.

Given:

  1. (a + b) / c = 6/5
  2. (b + c) / a = 9/2

First, let's rewrite these equations to isolate a, b, and c:

  1. a + b = 6c/5
  2. b + c = 9a/2

Now, we need to find a way to express (a + c) / b.

Let's add the two equations together:

a + b + b + c = 6c/5 + 9a/2 2b + a + c = 6c/5 + 9a/2

Rearranging terms, we get:

(2b + a + c) - 6c/5 - 9a/2 = 0 (2b - 6c/5 + a - 9a/2 + c) = 0

Solving for (a + c) / b, we get:

(a + c) / b = (2b - 6c/5 + 9a/2) / 2b (a + c) / b = (2 - 6c/5b + 9a/2b) / 2 (a + c) / b = 1 - 3c/5b + 9a/4b

This equation gives us the value of (a + c) / b in terms of a, b, and c. However, without specific values for a, b, and c, we cannot determine the exact value of (a + c) / b.

Therefore, the problem does not provide enough information to solve for the value of (a + c) / b.

This problem has been solved

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