If (a + b)/ c = 6/5 and (b + c ) / a = 9/2 then what is the value of (a + c )/b?Options9/57/117/411/7
Question
If (a + b)/ c = 6/5 and (b + c ) / a = 9/2 then what is the value of (a + c )/b?Options9/57/117/411/7
Solution
The problem is a system of two equations with three variables. To solve for the value of (a + c) / b, we need to manipulate the given equations to find a relationship between a, b, and c.
Given:
- (a + b) / c = 6/5
- (b + c) / a = 9/2
First, let's rewrite these equations to isolate a, b, and c:
- a + b = 6c/5
- b + c = 9a/2
Now, we need to find a way to express (a + c) / b.
Let's add the two equations together:
a + b + b + c = 6c/5 + 9a/2 2b + a + c = 6c/5 + 9a/2
Rearranging terms, we get:
(2b + a + c) - 6c/5 - 9a/2 = 0 (2b - 6c/5 + a - 9a/2 + c) = 0
Solving for (a + c) / b, we get:
(a + c) / b = (2b - 6c/5 + 9a/2) / 2b (a + c) / b = (2 - 6c/5b + 9a/2b) / 2 (a + c) / b = 1 - 3c/5b + 9a/4b
This equation gives us the value of (a + c) / b in terms of a, b, and c. However, without specific values for a, b, and c, we cannot determine the exact value of (a + c) / b.
Therefore, the problem does not provide enough information to solve for the value of (a + c) / b.
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