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Given an array of 6 numbers [6,8,19,48,9,90]and applying insertion sort, how many swaps must occur before the array is sorted?1 point42 6

Question

Given an array of 6 numbers [6,8,19,48,9,90]and applying insertion sort, how many swaps must occur before the array is sorted?1 point42 6

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Solution

Sure, let's go through the steps of the insertion sort algorithm on your array [6,8,19,48,9,90].

  1. [6,8,19,48,9,90] - Start from the first element, it is already sorted so no swaps are needed.
  2. [6,8,19,48,9,90] - Move to the next number, 8. It is also in the correct place, so no swaps are needed.
  3. [6,8,19,48,9,90] - Move to 19. It is also in the correct place, so no swaps are needed.
  4. [6,8,19,48,9,90] - Move to 48. It is also in the correct place, so no swaps are needed.
  5. [6,8,9,19,48,90] - Move to 9. It needs to be swapped with 48 and 19. So, 2 swaps are needed.
  6. [6,8,9,19,48,90] - Move to 90. It is in the correct place, so no swaps are needed.

So, in total, 2 swaps are needed to sort the array [6,8,19,48,9,90] using the insertion sort algorithm.

This problem has been solved

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