Given an array of 6 numbers [6,8,19,48,9,90]and applying insertion sort, how many swaps must occur before the array is sorted?1 point42 6
Question
Given an array of 6 numbers [6,8,19,48,9,90]and applying insertion sort, how many swaps must occur before the array is sorted?1 point42 6
Solution
Sure, let's go through the steps of the insertion sort algorithm on your array [6,8,19,48,9,90].
- [6,8,19,48,9,90] - Start from the first element, it is already sorted so no swaps are needed.
- [6,8,19,48,9,90] - Move to the next number, 8. It is also in the correct place, so no swaps are needed.
- [6,8,19,48,9,90] - Move to 19. It is also in the correct place, so no swaps are needed.
- [6,8,19,48,9,90] - Move to 48. It is also in the correct place, so no swaps are needed.
- [6,8,9,19,48,90] - Move to 9. It needs to be swapped with 48 and 19. So, 2 swaps are needed.
- [6,8,9,19,48,90] - Move to 90. It is in the correct place, so no swaps are needed.
So, in total, 2 swaps are needed to sort the array [6,8,19,48,9,90] using the insertion sort algorithm.
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