A car travels with a velocity of 80 km/h during the first half of its running time and then travels in the same direction at 40 km/h during the other half. Find the magnitude of the average velocity of the car.
Question
A car travels with a velocity of 80 km/h during the first half of its running time and then travels in the same direction at 40 km/h during the other half. Find the magnitude of the average velocity of the car.
Solution
To find the average velocity, we need to know the total distance traveled and the total time taken.
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Let's assume the total time for the journey is 2T (T for the first half and T for the second half).
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During the first half of the journey, the car travels at 80 km/h for T hours. So, the distance covered is 80T km.
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During the second half of the journey, the car travels at 40 km/h for T hours. So, the distance covered is 40T km.
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The total distance covered by the car is 80T + 40T = 120T km.
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The total time taken is 2T hours.
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The average velocity is the total distance divided by the total time. So, the average velocity is 120T/2T = 60 km/h.
So, the magnitude of the average velocity of the car is 60 km/h.
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